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4y^2+7y-36=0
a = 4; b = 7; c = -36;
Δ = b2-4ac
Δ = 72-4·4·(-36)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-25}{2*4}=\frac{-32}{8} =-4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+25}{2*4}=\frac{18}{8} =2+1/4 $
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